Find the cell potential of a galvanic cell zinc and copper ?

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Answer 1 · 2018-05-04T14:52:20

+1.101V

The 2 ionic half equations of the cell are given below.
Since zinc is more reactive than copper, zinc loses electrons more readily to form $Z n^{2 +}$ $Zn^(2+)$ ions.
$Z n (s) \to Z n^{2 +} (a q) + 2 e^{-}$ $Zn (s) -> Zn^(2+)(aq) +2e^-$
$C u^{2 +} (a q) + 2 e^{- \to} C u (s)$ $Cu^(2+)(aq) +2e^- -> Cu(s)$
Look up the standard potentials for the half-reactions.
$E^{o}$ $E^o$ for reduction of $c u^{2 +}$ $cu^(2+)$ is +0.339V
$E^{o}$ $E^o$ for oxidation of $Z n$ $Zn$ is +0.762V

Cell potential
= +0.339V +0.762V
= +1.101V