How do you write the first five terms of the sequence #a_n=2^n/3^n#?

Question

5357 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-05T08:05:21

#{a_n}={2/3,4/9,8/27,16/81,32/243}#

#a_n=2^n/3^n#

#a_1=2^1/3^1=2/3#

#a_2=2^2/3^2=4/9#

#a_3=2^3/3^3=8/27#

#a_4=2^4/3^4=16/81#

#a_5=2^5/3^5=32/243#

#{a_n}={2/3,4/9,8/27,16/81,32/243}#