What is the sum of the coefficients of the reactants for the balanced chemical equation ${2FeS}_{2} + {5O}_{2}$ $"2FeS"_2 + "5O"_2"$ $\to$ $rarr$ ${Fe}_{2} O_{2} + {4SO}_{2}$ $"Fe"_2"O"_2 + "4SO"_2"$ ?

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What is the sum of the coefficients of the reactants for the balanced chemical equation ${2FeS}_{2} + {5O}_{2}$ $"2FeS"_2 + "5O"_2"$ $\to$ $rarr$ ${Fe}_{2} O_{2} + {4SO}_{2}$ $"Fe"_2"O"_2 + "4SO"_2"$ ?

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Answer 1 · 2018-05-05T12:36:39

$7$ $7$

Explanation:

Balanced equation

${2FeS}_{2} + {5O}_{2}$ $"2FeS"_2 + "5O"_2"$ $\to$ $rarr$ ${Fe}_{2} O_{2} + {4SO}_{2}$ $"Fe"_2"O"_2 + "4SO"_2"$

The reactants are on the left-hand side of a chemical equation. So ${FeS}_{2}$ $"FeS"_2$ and $O_{2}$ $"O"_2"$ are the reactants for this equation. So add the coefficients $2$ $2$ and $5$ $5$ to get $7$ $7$ .

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What is the sum of the coefficients of the reactants for the balanced chemical equation ${2FeS}_{2} + {5O}_{2}$ $"2FeS"_2 + "5O"_2"$ $\to$ $rarr$ ${Fe}_{2} O_{2} + {4SO}_{2}$ $"Fe"_2"O"_2 + "4SO"_2"$ ?

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What is the sum of the coefficients of the reactants for the balanced chemical equation "2FeS"_2 + "5O"_2"2FeS2+5O2"2FeS"_2 + "5O"_2"rarr→rarr"Fe"_2"O"_2 + "4SO"_2"Fe2O2+4SO2"Fe"_2"O"_2 + "4SO"_2"?

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What is the sum of the coefficients of the reactants for the balanced chemical equation ${2FeS}_{2} + {5O}_{2}$ $"2FeS"_2 + "5O"_2"$ $\to$ $rarr$ ${Fe}_{2} O_{2} + {4SO}_{2}$ $"Fe"_2"O"_2 + "4SO"_2"$ ?