How do you simplify #2y(3y) + 16(y + 2) - 10#? Algebra Properties of Real Numbers When to Use the Distributive Property 1 Answer Ridinion K. May 5, 2018 #=6y^2+16y-22# Explanation: Start by multiplying out the terms: #2y*3y=6y^2# #16(y+2)=16y+32# Then write: #6y^2+16y+32-10=6y^2+16y-22# Answer link Related questions How do you simplify #(9-6y)/3#? How do you simplify #\frac{10x+8y-1}{2# using the distributive property? How do you use the distributive property to simplify #- \frac{6z - 2}{3}#? How do you simplify #6 + (x - 5) + 7#? How do you use the distributive property to simplify #(r + 3)(-5)#? What is the student error if a student rewrote #4(9x + 10)# as #36x + 10# ? How do you use the distributive property to calculate #6(19.99)# in your head? When do you use the Distributive Property? How do you use the distributive property to multiply #6(3r+4s)#? How do you use the distributive property to simplify #79(101)#? See all questions in When to Use the Distributive Property Impact of this question 2272 views around the world You can reuse this answer Creative Commons License