How do you simplify -sqrt((9+y)^2) if y<-10?

1 Answer
May 6, 2018

-sqrt((9+y)^2)>1

Explanation:

-sqrt((9+y)^2), where y<-10

Simplify the expression,

-sqrt((9+y)^2)

=-(9+y)

=-9-y

When y<-10,

-y>10

Subtract 9 from both sides,

-9-y>1

Hence,

-sqrt((9+y)^2)>1