How do you solve #-9(b)=2#?

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Answer 1 · 2018-05-06T10:47:53

#b = -0.222...#

#-9(b) = 2#

So you know that something multiplied by #-9 = 2#. That means that

#2 / -9 = b#

So

#2 / -9 = -0.222 ...#

#b = -0.222... #

which you can write as #-0.2# with a dot or a line above the digit #2#.

#b = -0.dot(2) = -0.bar(2)#

Answer 2 · 2018-05-06T12:47:57

#-0.bar2#

#-9b=2#

solve:

#=2/-9=-0.bar2#