What volume of 0.5 M nitric acid is needed to neutralize 25 mL of 0.2 M sodium hydroxide?

1 Answer
Al E.
May 6, 2018

Consider the acid-base reaction that takes place,

#HNO_3 + NaOH to H_2O + NaNO_3#

Our reactants are strong acids and bases, respectively. Hence, one molar equivalent of nitric acid is needed to neutralize the hydroxide ions that dissociate from #NaOH#.

Given,

#25"mL" * 0.2"M" = 5*10^-3"mol"# of #HNO_3#

Hence, we will need,

#5*10^-3"mol" * "L"/(0.5"mol") approx 10"mL"#

of nitric acid to accomplish the desired reaction, given your data.

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