What is the inverse function of #h(x)= sqrt(x + 5)#?

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Answer 1 · 2018-05-07T00:06:38

#=>h(x) = x^2 - 5#

We are given a function

#h(x) = sqrt(x+5)#

We want to find the inverse function. First, we swap
#h(x)# and #x#.

#x = sqrt(h(x)+5)#

Now we solve for #h(x)#.

#x^2 = h(x) + 5 #

#=>color(blue)(h(x) = x^2 - 5 )#