If 74.4 J of energy is applied to 9.52 g block of metal, the temperature increases by 10.7 °C. What is the specific heat capacity of this metal?

1 Answer
Nam D.
May 7, 2018

I get #0.73# joules per gram celsius.

Explanation:

The specific heat formula is,

#q=mcDeltaT#

  • #q# is the heat energy supplied

  • #m# is the mass of the substance

  • #c# is the specific heat capacity of the substance

  • #DeltaT# is the change in temperature

Rearranging for specific heat capacity, we get:

#c=q/(mDeltaT)#

Now, we just plug in values, to get the answer:

#c=(74.4 \ "J")/(9.52 \ "g"*10.7^@"C")#

#=(0.73 \ "J")/("g" \ ""^@"C")#

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