What is the inverse of f(x)=pi*arccos(x-1)+1?

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Answer 1 · 2018-05-07T02:10:28

#y = cos((x-1)/pi) + 1#

#y = pi arccos(x-1) + 1#

To take an inverse, you switch the x and y in this equation and solve for y:

#x = pi arccos(y-1) + 1#

#(x-1)/pi = arccos(y - 1)#

#cos((x-1)/pi) = cos(arccos(y - 1))#

#cos((x-1)/pi) = y - 1#

#y = cos((x-1)/pi) + 1#
Solved!