What force on a floating object displaces 0.6 m3 of water?

1 Answer
May 7, 2018

F = 5862.36N

Explanation:

Buoyancy force is equal to the weight of the displaced fluid(liquid or gas) by the object.

So we need to measure the weight of the displaced water by
F = color(red)(m)color(blue)(g)

F = "force"

color(red)(m = mass)
color(blue)(g = "gravitational strength" = 9.8 N/(kg))

but first, we need to find what is m
so from density formula

color(brown)(rho) = color(red)(m)/color(green)(V)

rearrange (solve for m):

color(red)(m) = color(brown)(rho) * color(green)(V)

color(brown)(rho = density, "and density of water is fixed" = 997(kg)/m^3)
color(green)(V = volume = 0.6m^3)

*if you are given the V in Liters you have to convert it to a cubic meter or cm *

color(red)(m = mass)

now substitute

m = 997(kg)/m^3*0.6m^3
m = 598.2kg

now find the force

F = mg

F = 598.2kg * 9.8N/(kg)

F = 5862.36N