How do you find the derivative of #1/3 (x^2-3x-5) * (2x-3)#?
1 Answer
May 7, 2018
Explanation:
#"differentiate using the "color(blue)"power rule"#
#•color(white)(x)d/dx(ax^n)=nax^(n-1)#
#"expand factors and distribute"#
#=1/3(2x^3-9x^2-x+15)#
#=2/3x^3-3x^2-1/3x+5#
#d/(dx)(2/3x^3-3x^2-1/3x+5)#
#=2x^2-6x-1/3#
