How do you solve #(c-8)/-2=(11-4c)/11#?

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Answer 1 · 2018-05-08T13:55:36

#c=22#

Multiply both sides by -22

#-22xx((c-8)/-2)=-22xx((11-4c)/11)#

Cancel

#11xx(c-8)=-2xx(11-4c)#

multiply out

#11c-88=-22+8c#

Subtract #8c# from both sides

#3c-88=-22#

Add 88 to both sides

#3c=66#

Divide both sides by 3

#c=22#