How do you factor $6 v^{3} - 4 v^{2} + 21 v - 14$ $6v^3 - 4v^2 + 21v - 14$ ?

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How do you factor $6 v^{3} - 4 v^{2} + 21 v - 14$ $6v^3 - 4v^2 + 21v - 14$ ?

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Answer 1 · 2018-05-09T02:57:04

$(2 v^{2} + 7) (3 v - 2)$ $(2v^2+7)(3v-2)$

Explanation:

$6 v^{3} - 4 v^{2} + 21 v - 14$ $6v^3-4v^2+21v-14$ =
$2 v^{2} (3 v - 2) + 7 (3 v - 2)$ $2v^2(3v-2)+7(3v-2)$ =
$(2 v^{2} + 7) (3 v - 2)$ $(2v^2+7)(3v-2)$

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How do you factor $6 v^{3} - 4 v^{2} + 21 v - 14$ $6v^3 - 4v^2 + 21v - 14$ ?

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How do you factor $6 v^{3} - 4 v^{2} + 21 v - 14$ $6v^3 - 4v^2 + 21v - 14$ ?