How do you evaluate #log_14 (1/14)#?
1 Answer
May 9, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#"let "log_(14)(1/14)=n#
#rArr1/14=14^n#
#rArr14^-1=14^nrArrn=-1#
