Solve the question ?
1 Answer
May 10, 2018
(i) Speed of particle as it reaches
v^2-u^2=2as
Inserting given values we get
v_B^2-3^2=2(2.5)(8)
=>v_B^2=40+9
=>v_B=7\ ms^-1
(ii) Let
As the particle slides down the inclined plane the downwards force along the incline
Downwards acceleration
Net force
=>F_f=0.8xx9.81xxsintheta-2
Now work done against force of friction
Angle between the force of friction and displacement is
(7.848sintheta-2)xx8=7
=>sintheta=(7/8+2)/7.848
=>theta=21.5^@