Please help me find the sum of the geometric series?

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Answer 1 · 2018-05-10T22:17:15

#"c". 211#

We have to add the values of #16(3/2)^(k-1)#, when k is 1, 2, 3, 4, and 5 to find our sum.

#16(3/2)^(1-1) + 16(3/2)^(2-1) +16(3/2)^(3-1) + 16(3/2)^(4-1) + 16(3/2)^(5-1)#

#16(3/2)^0 + 16(3/2)^1 +16(3/2)^2 + 16(3/2)^3 + 16(3/2)^4#

#(16 * 1) + (16 * 3/2) + (16 * 9/4) + (16 * 27/8) + (16 * 81/16)#

#16 + 48/2 + 144/4 + 432/8 + 1296/16#

#16 + 24 + 36 + 54 + 81 = 211#

#"c". 211#