How do you solve the following system using substitution?: #- 5x + y = - 3, 3x - 8y = 24#

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Answer 1 · 2018-05-11T06:41:36

#x = 0 and y = -3#

As per the question, we have

#-5x + y = -3#

#:. y = -3 + 5x# or #y = 5x - 3#

Now substituting the value for #y# in the second equation, we get

#3x - 8y = 24#

#:. 3x - 8(5x - 3) = 24#

#:. 3x - 40x + 24 = 24#

#:. -37x = 24 -24 #

#:. -37x = 0#

#:. x = 0#

Now, as we know the value of #x# we can calculate the value of #y# :

#y = 5x - 3#

#:. y = 5(0) - 3#

#:. y = 0 - 3#

#:. y = -3#

Therefore, # x = 0# and #y = -3# are the solution to this problem.