In a television tube, electrons are accelerated by a high voltage, and strike the screen with an average velocity of 4.04x10^6 m s^-1. Calculate the average de Broglie wavelength (in nm) of the electrons?

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Answer 1 · 2018-05-12T12:06:51

de Broglie wavelength #lambda# wavelength is given by the formula

#lambda=h/p#
where #h# is Planck's Constant #=6.6262 xx 10^-34\ Js#, and #p# is momentum of the object, #p="mass"xx"speed"#.

Taking #9.109×10^-31\ kg# as mass of electron, and inserting various vales we get

#lambda=(6.6262 xx 10^-34)/(9.109×10^-31xx4.04xx10^6)#
#=>lambda=1.80xx10^-10\ m#
#=>lambda=0.18\ nm#