How do you simplify #sqrt(9a^2)+sqrt(49b) -a + sqrtb#?

1 Answer
angry p.
May 12, 2018

2a+8 #sqrt(b)#

Explanation:

first, simplify the radicals.
#sqrt(9a^2)# becomes 3a because the root 9 is 3 and the root of a^2 is a.
#sqrt(49b)# becomes 7#sqrtb# because 49 can be simplified as a square but the value of b is unknown and not given as a square so it cannot.
Next, subtract and add.
3a-a=2a
because the radicals are treated like variables, #sqrtb# and 7#sqrtb# can be simplified as 8#sqrtb#.
the radicals do not change!
hope this helped

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