Question

A pole leans away from the sun at an angle of 6 degrees to the vertical. When the elevation of the sun is 58 degrees, the pole casts a shadow 46ft long on level ground. How long is the pole?

Answer 1

`(AB)/(sinangle ABC)=(BC)/(sinangleBAC)`

`(AB)/(sin(90^@-6^@))=46/(sin(180^@-58^@-(90^@-6^@))`

`=>AB=46/(sin38^@)xxsin84^@~~74.3ft`