Question

How do you solve `2x-5/9 = (7x+8)/9`?

Answer 1

First of all, you multiply everything by 9 so:
`2x-5/9 = (7x+8)/9`
`<=>18x - 5 = 7x+8`
then you bring x to the first class, and the numbers to the second
`<=>18x -7x = 8+5`
`<=>11x = 13`
`<=>x=13/11`

Answer 2

`x=13/11`

Explanation:

Multiply everything by 9 to remove the fractions.

`18x-5=7x+8`

add 5 to both sides

`18x=7x+13`

subtract `7x` from both sides

`11x=13`

`x=13/11`