Question

How do you evaluate the function `h(x)=3x-7` for #h(-2)?

Answer 1

See a solution process below:

Explanation:

For each occurrence of `color(red)(x)` substitute `color(red)(-2)` and evaluate the right side of the function:

`h(color(red)(x)) = 3color(red)(x) - 7` becomes:

`h(color(red)(-2)) = (3 xx color(red)(-2)) - 7`

`h(color(red)(-2)) = -6 - 7`

`h(color(red)(-2)) = -13`