Question

How to solve 3 1/2 - 2/3? I get getting 1 1/6 is that right

Answer 1

`2 5/6`

Explanation:

`3 1/2 - 2/3 = ?`

First, turn `3 1/2` into an improper fraction:

`3 1/2 rarr 7/2`

Now put that into the subtraction problem:

`7/2 - 2/3`

These two fractions do not have the same denominator, so they cannot be subtracted. Give them each a denominator of `6`, because this is their least common multiple.

Remember to multiply the top and bottom by the same number, to keep their correct value:

`7/2(3/3) rarr 21/color(orange)6`

`2/3(2/2) rarr 4/color(orange)6`

Now put them back into the subtraction problem and subtract the numerators:

`21/6 - 4/6`

`(21 - 4)/6`

`17/6 rarr 2 5/6`

I went ahead and turned it back into a mixed number. The most simplified version of this subtraction problem is `2 5/6`.

Answer 2

No, it is `2 5/6`

Explanation:

You would change both fractions to have common denominators. You should get `3 3/6` and `4/6`. Then, you would have to regroup since this is subtraction.

If you take away the 3 and add one whole to the `3/6`, you get `2 9/6`.

`2 9/6 - 4/6 = 2 5/6`

Hope this helps!

Answer 3

Sadly No. The answer is `2 5/6`

Explanation:

To take away or add fractions if you are every wondering if you are right you can convert them both to top-heavy fractions.

`3 1/2 = 7/2` and `2/3 = 2/3` (two thirds can't be simplified)

then you want to find a denominator which factors contain 2 and 3.

`2*3=6`
and convert the fractions above.

`7/2 = (7*3)/(2*3) = 21/6` and `2/3 = (2*2)/(3*2)=4/6`

Then you have `21/6 - 4/6 = 17/6 = 2 5/6`