How do you multiply #4m \cdot 7m ^ { 3}#?

3 Answers
May 14, 2018

#4m \cdot 7m ^ { 3}=(4*7)*(m)^[1+3]=28*m^4#

Explanation:

show below:

#4m \cdot 7m ^ { 3}=(4*7)*(m)^[1+3]=28*m^4#

not that

#x^n*x^m=x^[n+m]#

May 14, 2018

#28m^4#

Explanation:

Multiple #4# and #7#. you get #28# then add #m# and #m^3# you get #m^4#.

May 14, 2018

#28m^4#

Explanation:

An easy way of doing this would be expanding what each chunk means.
#4m = 4 * m#
and
#7m^3 = 7 * m * m * m #
So if you multiply #4m * 7m^3# you get
#4 * m * 7 * m * m * m#
You can then simplify this.
#4 * 7 = 28#
#m * m * m * m = m^4#
so #28 * m^4 = 28m^4#