What are the exact values of cos 150° and sin 150°?

1 Answer
May 16, 2018

#cos(150) = -sqrt(3)/2#
#sin(150) = 1/2#

Explanation:

First of all, observe that #150=180-30#.

Then, remember that we have

#cos(180-x) = -cos(x)#
#sin(180-x) = sin(x)#

Plug in #x=30# to get

#cos(180-30) = -cos(30)#
#sin(180-30) = sin(30)#

the answer comes from the fact that #cos(30)=sqrt(3)/2# and #sin(30)=1/2# are known values.