Question

Change into polar form `x^2+2y-1=0`?

Answer 1

`r(rcos^2theta+2sintheta)=1`

Explanation:

First, we need the two equations to convert which are:
`x=rcostheta`
`y=rsintheta`

Putting these in gives us:
`(rcostheta)^2+2rsintheta-1=0`

`r^2cos^2theta+2rsintheta=1`

`r(rcos^2theta+2sintheta)=1`