Question

How many molecules are there in 237 grams of `"CCl"_4`?

Answer 1

`9.28 * 10^23` molecules of `C"Cl_4`

Explanation:

Using stoichiometry, we need to convert grams of `(C"Cl_4)` to moles, then moles to molecules.

`237color(red)cancel(color(black)("g")) * (1color(red)cancel(color(black)("mol")))/(153.82color(red)cancel(color(black)("g"))) * (6.02*10^23"molecules")/(1color(red)cancel(color(black)("mol"))) = 9.28 * 10^23"` `"molecules"`