How do you solve #39< - 9+ 4n#?

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Answer 1 · 2018-05-17T15:03:01

#n > 12#

in interval notation

#n = (12, oo)#

#39 < -9 + 4n#

add #9# to both sides

#color(red)(9+)39 < cancel(-9 )+ 4n cancel(color(red)( +9))#

#48 < 4n#

divide both sides by 4

#12 < n#

#n > 12#

in interval notation

#n = (12, oo)#

12 is not included try to substitute 12 in #n# place you will get 48<48 which is wrong

try to substitute numbers greater than 12 you will get a correct answer.