How do you simplify $3 \sqrt{6} - 24 + 2 \sqrt{150}$ $3sqrt6-24+2sqrt150$ ?

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How do you simplify $3 \sqrt{6} - 24 + 2 \sqrt{150}$ $3sqrt6-24+2sqrt150$ ?

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Answer 1 · 2018-05-18T17:56:39

$13 \sqrt{6} - 24$ $13sqrt6-24$

Explanation:

Please note that $150 = 25 \cdot 6 = 5^{2} \cdot 6$ $150=25*6=5^2*6$
Therefore $2 \sqrt{150} = 2 \cdot 5 \sqrt{6} = 10 \sqrt{6}$ $2sqrt(150)=2*5sqrt6=10sqrt(6)$
Therefore $3 \sqrt{6} - 24 + 2 \sqrt{150} = 13 \sqrt{6} - 24$ $3sqrt6-24+2sqrt150= 13sqrt6-24$

We can, of course, write $24 = 4 \cdot 6 = 4 {(\sqrt{6})}^{2}$ $24= 4*6=4(sqrt6)^2$ ,
but $(13 - 4 \sqrt{6}) \sqrt{6}$ $(13-4sqrt6)sqrt6$ can hardly be said to be more simplified.

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How do you simplify $3 \sqrt{6} - 24 + 2 \sqrt{150}$ $3sqrt6-24+2sqrt150$ ?

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