How do you evaluate #2^10# please solve and give an example and explanation? I really need help please.

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Answer 1 · 2018-05-18T18:29:54

#2^10=2·2·2·2·2·2·2·2·2·2=1024#

The expresion #2^10# means that you have to repeat 2 as factor 10 times.

As you did long time ago, when you repeat a number adding a number of times you said for example #3+3+3+3=4·3=12#

Now the number you are repeating is as factor and the notation is #a^n=a·a·a·a····a# (n times)

Hope this helps

Answer 2 · 2018-05-18T18:37:21

#2^10=1024#

The powers of #10# are well known ...start with #1# and keep multiplying by #10# (just add another #0# each time. You get

#1," "10," "100," "1000," "10,000," "100,000 ....#

For the powers of #2#, start with #1# and keep multiplying by #2# which is the same as doubling each time. You get:

#1," "2," "4," "8," "16," "32," "64 .....#

#2xx2xx2xx2xx2xx2xx2xx2xx2xx2 =1024#

When you have multiplied by #2# a total of #10# times you have #2^10#

#

The answer will be #1024#

Answer 3 · 2018-05-18T19:11:12

#2^10=1024#

#2^10=2^4*2^4*2^2#

#:."when multiplying add the exponents together"#

#:.2^10=16*16*4=1024#

example:-

#:.3^16=3^4*3^4*3^4*3^2*3^2#

#:.3^16=81*81*81*9*9=43046721#

For #2^10:-#

"on your calculator(hp9s):- #press #2 "then press #x^y# then press #10# then press enter display#=1024#