Question

Please help?

http://prntscr.com/jjpusx

Answer 1

Since you know the angles must add up to 180 you have a:

`90, 45, 45` triangle

okay, the pathogarean theorem says `a^2 + b^2 = c^2`

we know c = 9 and we also know a=b

so: `2a^2 = 9^2`

`a^2 = 9^2/2`

`a = sqrt(9^2/2)`

`a = 9/sqrt2`

`a = (9sqrt2)/2`

`A=1/2bh`

just turn the triangle so the short sides are the base and height.

`1/2*(9sqrt2)/2*(9sqrt2)/2 = 20.25`

Answer 2

I tried this:

Explanation:

For problem 26 I got the following:

so the area will be:

`A=(9*4.5)/2=20.25"ft"^2`

For problem 27:

We know that the total perimeter is 44 units so the A (or B) bit will be:

`A=(44-20-4)/2=10`units:
and
`C=(20-4)/2=8`units

From Pythagoras:

`h=sqrt(10^2-8^2)=6` units

and the area of the trapezod:

`"Area"=1/2(20+4)*6=72` units squared