Help! The slant asymptote of f(x)=(6x^3-5x^2+3x)/(3x^2-x-14) intersects f where x=?

1 Answer
May 19, 2018

y=2x-1

x-int: x= 1/2

Explanation:

Use polynomial division to divide the numerator by the denominator the result is the line that is your slant asymptote.

(6 x^3 - 5 x^2 + 3 x)/(3 x^2 - x - 14)

6 x^3 - 5 x^2 + 3 x = (2 x - 1) × (3 x^2 - x - 14) + 30 x - 14

so the line y=2x-1 is your slant asymptote

the x-int is where y=0:

0=2x-1

x= 1/2