How do you write the first six terms of the sequence #a_n=3/-n#?

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Answer 1 · 2018-05-20T08:22:51

First six terms of the sequence are,

#-3, -3/2, -1, -3/4, -3/5, -2#

Given #a_n = 3/-n#

#a = 3/-1 = -3# as n = 1

#a_2 = 3/-2 = -3/2# as n = 2

Similarly, #a_3 = 3/-3 = -1#

#a_4 = 3/-4 = -3/4#

#a_5 = -3/5, a_6 = -2#