How do you multiply $(m^{6} n^{5}) (m^{8} n)$ $(m ^ { 6} n ^ { 5} ) ( m ^ { 8} n )$ ?

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How do you multiply $(m^{6} n^{5}) (m^{8} n)$ $(m ^ { 6} n ^ { 5} ) ( m ^ { 8} n )$ ?

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Answer 1 · 2018-05-20T18:39:26

$m^{14} n^{6}$ $m^14n^6$

Explanation:

Basically, this is $m^{6} \cdot n^{5} \cdot m^{8} \cdot n^{1}$ $m^6*n^5*m^8*n^1$
This is equal to $m^{6} \cdot m^{8} \cdot n^{5} \cdot n^{1}$ $m^6*m^8*n^5*n^1$
Using exponent rules, you should get $m^{14} n^{6}$ $m^14n^6$

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How do you multiply $(m^{6} n^{5}) (m^{8} n)$ $(m ^ { 6} n ^ { 5} ) ( m ^ { 8} n )$ ?

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Explanation:

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How do you multiply $(m^{6} n^{5}) (m^{8} n)$ $(m ^ { 6} n ^ { 5} ) ( m ^ { 8} n )$ ?