How do you know if #f(x)= 6x^3 - 2x# is an even or odd function?

1 Answer
May 20, 2018

#f(-x)=-f(x)#, therefore our function is odd.

Explanation:

To find out we need to test out how the value of #f(-x)# is compared to #f(x)#. According to https://en.wikipedia.org/wiki/Even_and_odd_functions

if #f(x)=f(-x) -># this is an even function.
if #f(-x)=-f(x) -># this is an odd function.

So let's see what happens if you input (-x) in f(x):
#f(-x)=6(-x)^3-2(-x)#
#=-6x^3+2x#
#=-(6x^3-2x)#
#=-f(x)#

Conclusion, our function is odd.