Evaluate the logarithm. #log_6 (1/216)# how?

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Answer 1 · 2018-05-20T23:42:43

#-3#

Let the value of #log_6(1/216)# be #x#

#=> x = log_6(1/216)#

#=> 6^x = 1/216#

#=> 6^x = 1/6^3#

#=> 6^x = 6^-3#

#=> x = -3#

∴ Value of #log_6(1/216)# is #-3#