How do you solve for #r# : #q - 3r = 2# ?
1 Answer
May 21, 2018
Explanation:
#"isolate the term in r"#
#"add "3r" to both sides"#
#qcancel(-3r)cancel(+3r)=2+3r#
#rArrq=3r+2#
#"subtract 2 from both sides"#
#rArrq-2=3r#
#"divide both sides by 3"#
#(q-2)/3=(cancel(3) r)/cancel(3)#
#rArrr=(q-2)/3=1/3(q-2)#