Question

Given the function `y=(x^2-36)/(x^3+36-5x-30)` evaluate f(-6)?

Answer 1

`f(-6)=0`

Explanation:

`f( x) = y = (x^2-36)/(x^3+36-5 x-30)` or

`f( x) = ((x+6)(x-6))/(x^3+36-5 x-30)`

`f( -6) = ((-6+6)(-6-6))/((-6)^3+36-5 (-6)-30)=0`

`f(-6)=0` [Ans]