Question

How do you solve? y=ln(x^2+1)

Is derived y=ln(x^2+1)

Answer 1

Please see the explanation.

Explanation:

`y=ln(x^2+1)`

Solving a function means to find the roots or zeros of the function. On the graph of a function the solution(s) is the point(s) where the curve touches or crosses the x-axis AKA the x-intercept(s). To find the x-intercepts of a function we need to set y to zero and solve for x, therefore in this case we have:

`ln(x^2+1)=0`
`x^2+1=e^0=1`
`x^2=0`
`x=0`

Notice the graph in the link below, the graph touches the x-axis at only one point i.e: (0, 0).

https://www.desmos.com/calculator/yyley7aguo