Question

How do you find the two consecutive integers whose sum is 223?

Answer 1

See a solution process below:

Explanation:

First, let's cal the first integer we are looking for: `n`

Then, because we are looking for consecutive integers the second integer we are looking for can be written as: `n + 1`

We know these two integers sum to 223. Therefore, we can write this equation and solve for `n`:

`n + (n + 1) = 223`

`n + n + 1 = 223`

`1n + 1n + 1 = 223`

`(1 + 1)n + 1 = 223`

`2n + 1 = 223`

`2n + 1 - color(red)(1) = 223 - color(red)(1)`

`2n + 0 = 222`

`2n = 222`

`(2n)/color(red)(2) = 222/color(red)(2)`

`(color(red)(cancel(color(black)(2)))n)/cancel(color(red)(2)) = 111`

`n = 111`

• The First integer is: `111`

• The Second integer is: `111 + 1 = 112`

Solution Check:

`111 + 112 = 223`