Question

Could i have some help please ??

Answer 1

Well, we can tell you the molar quantity associated with `1*g` of sucrose...

Explanation:

`"Number of moles"="mass of stuff"/"molar mass of substance"`

`(1.00*g)/(underbrace(342.30* g*mol^-1)_"molar mass of sucrose")=2.92xx10^-3*mol`

Answer 2

0.002 92 mol sucrose; 0.003 90 mol palmitic acid

Explanation:

Moles of sucrose

The formula of sucrose is `"C"_12"H"_22"O"_11`.

`"M_text(r) = 342.30`

`"Moles of sucrose" = 1.00 color(red)(cancel(color(black)("g sucrose"))) × "1 mol sucrose"/(342.30 color(red)(cancel(color(black)("g sucrose")))) = "0.002 92 mol sucrose"`

Moles of palmitic acid

The formula of palmitic acid is `"C"_16"H"_32"O"_2`.

`"M_text(r) = 256.42`

`"Moles of palmitic acid" = 1.00 color(red)(cancel(color(black)("g palmitic acid"))) × "1 mol palmitic acid"/(256.42 color(red)(cancel(color(black)("g palmitic acid")))) = "0.003 90 mol palmitic acid"`