How do you solve #-9= - 9/ 8( 5) + b#?

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Answer 1 · 2018-05-22T17:52:00

#b=-27/8#

#-9= - 9/ 8( 5) + b#

#-9= - 9/ 8( 5/1) + b#

#-9= - 45/ 8 + b#

multiply both sides of the equation by 8 to remove the fraction:

#8*(-9)= 8(- 45/ 8 + b)#

#-72 = -45 + 8b#

add 45 to both sides of the equation:

#-27 = 8b#

divide both sides of the equation by 8:

#-27/8 = b#

#b=-27/8#