Question

How do you solve `8( x - 6) \leq - 96`?

Answer 1

Re-organize the expression and you will find that `xle-6`

Explanation:

First, we'll divide both sides by the coefficient used on the left-hand side (8):

`(cancel(8)(x-6))/color(red)(cancel(8))le(-96)/color(red)(8)`

`x-6le-12`

next, we'll move the 6 to the right hand side by adding 6 to both sides:

`xcancel(-6)color(red)(cancel(+6))le-12color(red)(+6)`

`color(green)(xle-6)`

Answer 2

`x<=6`

Explanation:

`"distribute bracket on left side of the inequality"`

`rArr8x-48<= -96`

`"add 48 to both sides"`

`rArr8x<= -48`

`"divide both sides by 8"`

`rArrx<= -6`

`x in(-oo,-6)larrcolor(blue)"in interval notation"`