How do i solve this? An airplane heads N60°E at 600 mi/h in still air. A tail wind begins to blow in the direction N30°E at 50 mi/h. Find the resulting speed of the airplane and its resulting direction of travel. Draw a diagram
1 Answer
Let us first understand what does
It is: We go
Now lets take east as
As such airplane's
Let
R_x=v_(sx)+v_(wx)
=>R_x=600\ cos 30^@+50\ cos 60^@
=>R_x=600sqrt3/2+50xx1/2
=>R_x=519.62\ mph
Similarly, for components along
R_y=v_(sy)+v_(wy)
=>R_y=600\ sin 30^@+50\ sin 60^@
=>R_y=600xx1/2+50xxsqrt3/2
=>R_y=343.30\ mph
Now
=>R=sqrt((519.62)^2+(343.30)^2)
=>R=622.8\ mph
If
theta=tan^-1(R_y/R_x)
theta=tan^-1(343.30/519.62)
theta=33.5^@
This can also be written as"N"56.5^@"E"
Please make a diagram and post here.