How do you solve the system of equations 3x−5y=24 and x−2y=6?

1 Answer
Shiva Prakash M V
May 23, 2018

x=18
y=6

Explanation:

3x−5y=24−−−−−−(1)
x−2y=6−−−−−−−−(2)
from (2),
x=2y+6
(1) becomes
3(2y+6)−5y=24
6y+18−5y=24
y+18=24
y=24−18
y=6
x=2(6)+6
x=12+6
x=18

Check:
lhs=3x−2y=3(18)−5(6)=54−30=24=rhs
lhs=x−2y=18−2(6)=18−12=6=rhs

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