If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 2/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 6 seconds?

Question

1638 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-23T14:58:09

The power is #=85.68MW#

The mass of the rocket is #m=3500000kg#

The acceleration of the rocket is #a=2/5ms^-2#

The acceleration due to gravity is #=9.8ms^-2#

According to Newton's second Law, the net force on the rocket is

#F=m(a+g)=3500000*(9.8+2/5)=35700000N#

Assuming that the initial velocity of the rocket is #u=0ms^-1#

The velocity after #t=6s# is

#v=u+at=0+2/5*6=2.4ms^-1#

The power is

#P=Fv=35700000xx2.4=85.68MW#