We have A(x) = x^2-6x+4 the question is factorise A(x) +5?

1 Answer

#A(x)=(x-3)*(x-3)#

Explanation:

We have,

#A(x)=x^2-6x+4#

So,

#color(white)(xxx)A(x)+5=(x^2-6x+4)+5#

#rArr A(x)=x^2-6x+9#

#rArr A(x)=(x)^2 - 2 * x * 3 + (3)^2#

#rArr A(x) = (x- 3)^2#

#rArr A(x) = (x - 3) (x - 3)#

Note that

#color(red)[a^2x^2-bx+c^2=(sqrt(a^2x^2)-sqrt(c^2))^2=(ax-c)^2]# [Where #b = 2ac#]