How do you factor?

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How do you factor?

m^2-11m+18=0

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Answer 1 · 2018-05-24T05:04:16

Factors are: $(m - 2) (m - 9) = 0$ $(m-2)(m-9)=0$
$m = 2$ $m=2$
$m = 9$ $m=9$

Explanation:

Trying to factor by splitting the middle term:

Step 1
Factoring $m^{2} - 11 m + 18$ $m^2-11m+18$

The first term is, $m^{2}$ $m^2$ its coefficient is $1$ $1$ .
The middle term is, $- 11 m$ $-11m$ its coefficient is $- 11$ $-11$ .
The last term, "the constant", is $+ 18$ $+18$

Step 2
Find two factors of $18$ $18$ whose sum equals the coefficient of the middle term, which is $- 11$ $-11$ .

$- 18 + (- 1) = - 19$ $-18 + (-1) = -19$
#-9 + (-2) = -11 -----> This is the one

Step 3
Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -2
$m^{2} - 9 m - 2 m + 18$ $m^2 - 9m - 2m +18$

$m (m - 9) - 2 (m - 9)$ $m(m-9) - 2(m-9)$ ------> pulling out the like factors

$(m - 2) . (m - 9) = 0$ $(m-2).(m-9) = 0$

$m - 2 = 0$ $m-2=0$ -------> $m = 2$ $color(red)(m=2)$

$m - 9 = 0$ $m-9=0$ ------->. $m = 9$ $color(red)(m=9)$

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How do you factor?

m^2-11m+18=0

1 Answer

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