Question

What is the volume of 22 moles of oxygen gas at STP?

22.4L/mol at STP

Answer 1

`492.8\ "L"`

Explanation:

`1` mol of any gas at `"STP"` occupies `22.4\ "L"` of volume.

So, `22` mol of oxygen will occupy

`22 cancel"mol" × 22.4 "L"/cancel"mol" = "492.8 L"`